60=14x+2x^2

Solution for 60=14x+2x^2 equation:

60=14x+2x^2

We move all terms to the left:

60-(14x+2x^2)=0

We get rid of parentheses

-2x^2-14x+60=0

a = -2; b = -14; c = +60;
Δ = b2-4ac
Δ = -142-4·(-2)·60
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-26}{2*-2}=\frac{-12}{-4}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+26}{2*-2}=\frac{40}{-4}
=-10
$